Power transmissionCalculating the ?i? reduction ratio
| Calculating the “i” reduction ratio |
| The reduction ratio between two pinions is obtained by dividing the number of cogs in the pinion driven by the number of cogs in the drive pinion. |
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| | 5th gear | Tapered unit |
| Drive Pinion (main) | 43 (Z1 Main) | 18 (Z1 Pinion) |
| Driven Pinion (secondary) | 36 (Z2 Secondary) | 61 (Z2 Crown) |
| ig = Reduction ratio in a gear |
| ia = Reduction ration for the drive train |
| itotal = Total reduction ratio |
| It is obtained by multiplying the reduction ratios from the highest gear and the cone unit. |
| itotal = iG x iA = 0,837 x 3,389 = 2,836 |
| 1)
| Z1 = Number of cogs on the drive pinion, Z2 = number of cogs on the driven pinion. |
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01 Transmission
